-16t^2=-940

Solution for -16t^2=-940 equation:

-16t^2=-940

We move all terms to the left:

-16t^2-(-940)=0

We add all the numbers together, and all the variables

-16t^2+940=0

a = -16; b = 0; c = +940;
Δ = b2-4ac
Δ = 02-4·(-16)·940
Δ = 60160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60160}=\sqrt{256*235}=\sqrt{256}*\sqrt{235}=16\sqrt{235}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{235}}{2*-16}=\frac{0-16\sqrt{235}}{-32}
=-\frac{16\sqrt{235}}{-32}
=-\frac{\sqrt{235}}{-2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{235}}{2*-16}=\frac{0+16\sqrt{235}}{-32}
=\frac{16\sqrt{235}}{-32}
=\frac{\sqrt{235}}{-2}
$